Ocean waves travel in to the beach at an average velocity of 2.5 m s . If these waves come in 4 seconds apart, what is the average distance between the wave peaks, considering the formula V= d t ?

Respuesta :


[tex]2.5 \times 4 [/tex]

Answer : Average distance is 10 m.

Explanation :

It is given that,

Average velocity of the wave, [tex]v=2.5\ m/s[/tex]

Time, [tex]T=4\ s[/tex]

So, frequency [tex]\nu=\dfrac{1}{T}=\dfrac{1}{4}\ Hz[/tex]

We know that the average distance between the wave peaks is called as wavelength.

The relation between the wavelength, frequency and the time period is :

[tex]\lambda=\dfrac{v}{\nu}[/tex]

[tex]\lambda=\dfrac{2.5\ m/s}{\dfrac{1}{4\ s}}[/tex]

[tex]\lambda=10\ m[/tex]

So, the average distance between the wave peaks is 10 m.