Answer:
[tex]\frac{(2n+5)(7n+3)}{2n(2n+3)(5n-1)}[/tex]
Step-by-step explanation:
At first we simplify each fraction
[tex]\frac{10n^{2}+23n-5 }{4n^{2}+6n}=\frac{(5n-1)(2n+5)}{2n(2n+3)}[/tex]
[tex]\frac{25n^{2}-10n+1}{7n+3}=\frac{(5n-1)(5n-1)}{7n+3}[/tex]
We will reverse the fraction after the division sign and change the division sign to multiplication sign
[tex]\frac{(5n-1)(2n+5)}{2n(2n+3)}[/tex] × [tex]\frac{(7n+3)}{(5n-1)(5n-1)}[/tex]
Simplify the two fractions
[tex]\frac{(2n+5)(7n+3)}{2n(2n+3)(5n-1)}[/tex]⇒Simplest form
