a. What is the change in internal energy if 500 J of heat is added to a system and 100 J of work is done by the system? Show your work.

b. Describe two sets of conditions of heat and work that cause a decrease in internal energy.

c. Write one or two sentences describing how a heat pump works.

d. A neatly arranged closet is a very orderly system and has low entropy. Why is it safe to assume that this did not happen naturally? Write one or two sentences explaining your answer.

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ugmichail ugmichail · Answer 1 · 2019-02-27T13:56:57+01:00

a) dU=Q-A, so DU=400 J

b) When you decrease heat while increase work and when you increase work while decreasing heat.

c) It takes heat from colder places and releases the heat to warmer places.

d) Because the order there is made by human.

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priyankatutor priyankatutor · Answer 2 · 2022-01-13T09:59:23+01:00

The work done by the system is 400 J. The internal energy of the system decreases with an increase in the work.

It is the sum of all energies within a system. Heat play a major role in internal energy of a system.

The work done on the system can be calculated by the formula,

[tex]\Delta U = Q-W[/tex]

Where,

[tex]\Delta U \\[/tex]- change in internal energy of the system = 500 J

[tex]Q[/tex]- energy absorbed = 100 J

[tex]W\\[/tex] - work

Put the values in the in the equation,

500 J = 100 J -W

W = 500 J - 100 J

W = 400 J

B) As work done by the system increase and the heat added to the system decrease, the internal energy of the system decrease.

Therefore, the work done by the system is 400 J. The internal energy of the system decreases with an increase in the work.

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