First convert the 590.0 grams of water to liters of water.
590.0 grams x (1 L / 1000 grams) = 0.59 L
Since we're dealing with concentration, recall this formula:
Molarity (M) = (moles of solute) / (liters of solution)
We know the Molarity and the Liters
0.82 M = (moles) / 0.59 L
To find the moles multiply 0.59 on both sides.
The result is 0.4838 moles of CaCl (the solute).
Then change moles into grams because the question wants grams.
In order to convert the moles of a substance to grams, you will need to multiply the mole value of the substance by its molar mass which is 110.986.
(0.4838 moles CaCl2) x (110.986 g CaCl)/ 1 mol CaCl2
The mass of the CaCl2 is 53.7 g.
A solution is composed of a solute and a solvent which are mixed together.
In this case, we have the following information;
Mass of water = 590.0 grams
Concentration of solution = 0.82 M
Since the density of water is 1 g/cm^3, volume of the solution is 590.0 cm^3 or 0.59 L
Number of moles = concentration * volume
Number of moles = mass/molar mass
Molar mass of CaCl2 = 111 g/mol
Hence, let the mass of teh solute be x
x/111 = 0.82 M * 0.59 L
x = 0.82 M * 0.59 L * 111
x = 53.7 g
The mass of the CaCl2 is 53.7 g.
Learn more about solution: https://brainly.com/question/1190311
