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Entertainment For a scene in a movie, a sack of money is dropped from the roof
of a 600-foot skyscraper. The height of the sack above the ground in feet is given by h = -16t2 + 600, where t is the time in seconds. How long will it take the sack to reach the ground?
Round to the nearest tenth of a second.

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Respuesta :

znk

Answer:

6.1 s  

Step-by-step explanation:

h = -16t² + 600

When the sack reaches the ground, h = 0.

   0 = -16t² + 600

16t² = 600

  t² = 600/16

  t² = 37.5

   t = 6.1 s

It will take 6.1 s for the sack to reach the ground.

It  takes  6.1 s for the sack to reach the ground.

We have given that the expression

h = -16t² + 600

What is the height when sack reaches the ground?

at ground height is 0

Therefore,When the sack reaches the ground, h = 0.

[tex]0 = -16t^2 + 60016t^2 = 600 t^2 = 600/16 t^2 = 37.5 t = 6.1 s[/tex]

Therefore ,It will take 6.1 s for the sack to reach the ground.

To learn more about the dropping particle height visit:

https://brainly.com/question/15704650

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