Answer:
The force will double
Explanation:
The electrostatic force between two electric charge is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges
In this problem, at the beginning the two charges are equal, so
q1 = q2 = q
and the force between them is
[tex]F=k\frac{q^2}{r^2}[/tex]
Later, one of the two charges is doubled in magnitude:
[tex]q_1 =2q\\q_2 = q[/tex]
So the new force will be
[tex]F'=k\frac{(2q)(q)}{r^2}=2k\frac{q^2}{r^2}=2F[/tex]
so, the force has doubled.
