Based on the graph, which statement BEST describes the acceleration of the two objects?
A) Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.
B) Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.
C) Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration.
D) Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.

Based on the graph which statement BEST describes the acceleration of the two objects A Acceleration 1 no acceleration Acceleration 2 negative acceleration B Ac class=

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Answer:

C) Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration.

Explanation:

In a velocity-time graph, the acceleration corresponds to the slope of the curve.

In fact, acceleration is defined as the ratio between the change in velocity and the time interval:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

However, we see that in a velocity-time graph, [tex]\Delta v[/tex] corresponds to the increment in the y-variable ([tex]\Delta y[/tex]), while [tex]\Delta t[/tex] corresponds to the increment in the x-variable ([tex]\Delta x[/tex]). Therefore, acceleration can also be written as

[tex]a=\frac{\Delta y}{\Delta x}[/tex]

which is exactly the definition of slope of the curve.

Now we notice that:

- For object 1, the slope is constant: this means that the acceleration is constant

- For object 2, the slope varies: this means that the acceleration varies as well

Answer:C) Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration.

Explanation:

The lines on the graph are best described by the following: Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration. Acceleration 1 DOES show positive acceleration, but since the slope of the line does not vary, the acceleration is constant. Acceleration B has a varied slope, and therefore, a varied acceleration. It does happen to be positive and negative. For zero acceleration, the slope slope would be zero and the line horizontal.