[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{3}{ h},\stackrel{2}{ k})\qquad \qquad radius=\stackrel{5}{ r} \\\\\\ (x-3)^2+(y-2)=5^2\implies (x-3)^2+(y-2)=25[/tex]
Answer:
(x-3)² + (y-2)² = 25
Step-by-step explanation:
apeex
