Explanation:
Electric field intensity E is defined as the electric (Coulomb) force on a unit test (1 C) charge. Mathematically, it is given by :
[tex]E=\dfrac{F}{q}[/tex]
The electric force is given by :
[tex]F=k\dfrac{qQ}{d^2}[/tex]
Where
Q and q are electric charges
d is the distance between charges
The electric field intensity at a distance d from the center is given by :
[tex]E=\dfrac{k\dfrac{qQ}{d^2}}{q}[/tex]
So,
[tex]E=\dfrac{kQ}{d^2}[/tex]
Hence, this is the required solution.
