Answer:
a) Q=19600W b)Q=60W
Explanation:
q=k.(T₀-T₁)/x
a)
T₀=inside temperature (K)= 273+15=288K
T₁=outside temperature(K)= 273-20=253K
x=5x10⁻³m
k=1.4W/m.K
∴q=9800W/m² ⇒ Q=q.Surface
Q=9800W/m² . 1m . 2m = 19600W.
b)
T₀=inside temperature (K)= 273+10=273K
T₁=outside temperature(K)= 273-15=258K
x=10x10⁻³m
k=0.024W/m.K
∴q=60W/m² ⇒ Q=q.Surface
Q=60W/m² . 1m . 2m = 120W.