Answer: The average kinetic energy of hydrogen atoms is [tex]1.19562\times 10^{-19}J[/tex]
Explanation:
To calculate the average kinetic energy of the atom, we use the equation:
[tex]K=\frac{3}{2}kT[/tex]
where,
K = average kinetic energy
k = Boltzmann constant = [tex]1.3807\times 10^{-23}J/K[/tex]
T = temperature = [tex]5500^oC=[5500+273]K=5773K[/tex]
Putting values in above equation, we get:
[tex]K=\frac{3}{2}\times 1.3807\times 10^{-23}J/K\times 5773K\\\\K=1.19562\times 10^{-19}J[/tex]
Hence, the average kinetic energy of hydrogen atoms is [tex]1.19562\times 10^{-19}J[/tex]
