Answer : The work done by the system is, 2.2722 J
Explanation :
The expression used for work done in reversible isothermal expansion will be,
[tex]w=nRT\ln (\frac{V_2}{V_1})[/tex]
where,
w = work done = ?
n = number of moles of gas  = 0.00100 mole
R = gas constant = 8.314 J/mole K
T = temperature of gas  = [tex]25^oC=273+25=298K[/tex]
[tex]V_1[/tex] = initial volume of gas  = 25 mL
[tex]V_2[/tex] = final volume of gas  = 75 mL
Now put all the given values in the above formula, we get:
[tex]w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})[/tex]
[tex]w=2.722J[/tex]
Therefore, the work done by the system is, 2.2722 J
