Respuesta :
Answer:
20 mA
Explanation:
We have given that the transformer convert 120 V to 12 V means it is a step down transformer
The turn ratio of the transformer is given as [tex]a=\frac{N_1}{N_2}=\frac{V_1}{V_2}=\frac{120}{12}=10[/tex] here [tex]V_![/tex] is primary voltage and [tex]V_2[/tex] is secondary voltage
As the voltage decreases from primary to secondary so current will increase from primary to secondary
We have given output current that is secondary current so primary that is input current will be less
So input current [tex]=\frac{200}{10}=20mA[/tex]
The input current of the plugin transformer will be [tex]I_{2}=20mA[/tex]
What will be the current input to the transformer?
Since the transformer is converting the voltage from 120V to 12 V it means that the transformer is a step-down transformer.
The turn ratio of the transformer is given as
[tex]a=\dfrac{N_{1}}{N_{2}} =\dfrac{V_{1}}{V_{2}} =\dfrac{I_{1}}{I_2}[/tex]
Here
[tex]N_1[/tex]= Number of the turns in the primary coil
[tex]N_2[/tex]= Number of the turns in the secondary coil
[tex]V_1[/tex]=Voltage in the primary coil =120V
[tex]V_2[/tex]=Volatge int the secondary coil=12V
[tex]I_1[/tex]=Current in the primary coil=?
[tex]I_2[/tex]=Curremt in the secondary coil=200 mA
Now from the turn ratio
[tex]a=\dfrac{N_{1}}{N_{2}} =\dfrac{V_{1}}{V_{2}} =\dfrac{I_{1}}{I_2}[/tex]
[tex]I_{1}=\dfrac{I_{2}V_{2}}{V_1}[/tex]
So input current
[tex]I_{1}=\dfrac{12\times 200}{120} =20\ mA[/tex]
Thus the input current of the plugin transformer will be [tex]I_{2}=20mA[/tex]
To know more about Transformers follow
https://brainly.com/question/9719792
