Respuesta :

I assume you mean (x^2 - 15*x - 36) / (5x - 60). Notice that you can factor a 5 out of the denumerator (the bottom), to get 5 * (x - 12). You could then try factoring the numerator (the top part), and you will probably be able to cancel out a term on top and bottom.

Answer: The simplified value of the given expression will be [tex]\frac{x-3}{5}[/tex]

Step-by-step explanation:

The expression of the given statement becomes:

[tex]\frac{x^2-15x+36}{5x-60}[/tex]

To solve the above expression, we need to factorize the quadratic equation by middle term splitting:

[tex]\Rightarrow \frac{x^2-15x+36}{5x-60}=\frac{x^2-12x-3x+36}{5(x-12)}\\\\\Rightarrow \frac{x^2-12x-3x+36}{5(x-12)}=\frac{x(x-12)-3(x-12)}{5(x-12)}\\\\\Rightarrow \frac{x(x-12)-3(x-12)}{5(x-12)}=\frac{(x-3)(x-12)}{5(x-12)}[/tex]

Omitting out the factor '(x - 12)' from denominator and numerator, we get:

[tex]\Rightarrow \frac{(x-3)(x-12)}{5(x-12)}=\frac{x-3}{5}[/tex]

Hence, the simplified value of the given expression will be [tex]\frac{x-3}{5}[/tex]

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