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Two propane-butane mixtures are contained in separate containers. The first mixture contains 30 wt% propane, and the second contains 60 wt% propane. If 1,000 g of the first mixture is combined with 1,200 g of the second, what are the mass and compositions of the product?

Respuesta :

Answer:

750 grams is the mass of product and 34.09% is the compositions of the product.

Explanation:

Container 1 , 30% of propane by mass:

Container 2 , 60% of propane by mass:

Mass of mixture in container-1 = 1000 g

Mass of propane in 1000 g of mixture = m

m= [tex]\frac{30}{100}\times 1000 g= 300g[/tex]

Mass of mixture in container-2 = 1200 g

Mass of propane in 1200 g of mixture = m'

m'= [tex]\frac{60}{100}\times 1200 g= 720 g[/tex]

After mixing 1000 grams and 1200 grams of mixture

Final mass of mixtures = 1000 g + 1200 g = 2200 g

Final mass of propane = 300 g+ 720 g = 750 g

Composition of propane after mixing of mixtures :

[tex]\%=\frac{750 g}{2200 g}\times 100=34.09\%[/tex]

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