Answer:
x = [tex]ye^{2a}[/tex]
Step-by-step explanation:
Data provided:
ln(x) − ln(y) = 2a
Now,
The using the following properties of log function,
we have
log(A) - log(B) = [tex]\ln(\frac{A}{B})[/tex]
and,
ln(a) = b is equivalent to a = [tex]e^b[/tex] (here e is exponential )
ln(e) = 1
therefore,
the above equation transforms as:
[tex]\ln(\frac{x}{y})[/tex] = 2a
taking anti-ln both sides,
we get
[tex]\frac{x}{y}[/tex] = [tex]e^{2a}[/tex]
or
x = [tex]ye^{2a}[/tex]
