A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the Earth to the surface. If the satellite had a weight at the surface of 4000 N, what is the force of gravity (weight) of the satellite when it is in its orbit? Give your answer in newtons, N.

Respuesta :

Answer:

995 N

Explanation:

Weight of surface, w= 4000N

Gravitational constant, g, is taken as 9.81 hence mass, m of surface is W/g where W is weight of surface

m= 4000/9.81= 407.7472

Using radius of orbit of 6371km

The force of gravity of satellite in its orbit, [tex]F=\frac {GMm}{(2r)^{2}}=\frac {GMm}{4(r)^{2}}[/tex]

Where [tex]G=6.67*10^{-11}[/tex] and [tex]M=5.94*10^{24}[/tex]

[tex]F=\frac {(6.67*10^{-11}*5.94*10^{24}*407.7472)}{4*({6.371*10^{6}m)}^{2}}[/tex]

F= 995.01142 then rounded off

F=995N