Answer:
0.167 m/s²
4.0915 m
1.169 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
m = Mass
The resultant force on the boat = 1500-1300 = 200 N
[tex]F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{200}{1200}\\\Rightarrow a=0.167\ m/s^2[/tex]
Acceleration of the boat is 0.167 m/s²
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times 7+\frac{1}{2}\times 0.167\times 7^2\\\Rightarrow s=4.0915\ m[/tex]
The boat will travel 4.0915 m in 7 seconds
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 0.167\times 4.0915+0^2}\\\Rightarrow v=1.169\ m/s[/tex]
The velocity of the boat at the end of 7 s is 1.169 m/s
