Answer:
[tex]P = 3.55 \times 10^5 Pa[/tex]
Explanation:
As we know that water from the fountain will raise to maximum height
[tex]H = 26.0 m[/tex]
now by energy conservation we can say that initial speed of the water just after it moves out will be
[tex]\frac{1}{2}mv^2 = mgH[/tex]
[tex]v = \sqrt{2gH}[/tex]
[tex]v = \sqrt{2(9.81)(26)}[/tex]
[tex]v = 22.6 m/s[/tex]
Now we can use Bernuolli's theorem to find the initial pressure inside the pipe
[tex]P = P_0 + \frac{1}{2}\rho v^2[/tex]
[tex]P = 10^5 + \frac{1}{2}(1000)(22.6^2)[/tex]
[tex]P = 3.55 \times 10^5 Pa[/tex]
