Answer:
x=3 and y=−1 AND/OR (3, 1)
Step by Step:
1) Multiply the first equation by 3, and multiply the second equation by 1.
3(2x−6y=12)
1(−6x−4y=−14)
2) Becomes:
6x−18y=36
−6x−4y=−14
3) Add these equations to eliminate x:
−22y=22
4) Then solve −22y = 22 for y:
−22y−22=22−22 (Divide both sides by -22)
y=−1
5) Now that we've found y let's plug it back in to solve for x.
6) Write down an original equation:
2x−6y=12
7) Substitute−1for y in2x−6y=12:
2x − (6) (−1) =12
2x + 6 = 12 (Simplify both sides of the equation)
2 x + 6 + − 6 = 12 + −6 (Add -6 to both sides)
2 x = 6
2 x 2 = 62 (Divide both sides by 2)
x = 3
