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jenny solves x^2 + 2x- 3 = 0 and finds the solutions are x = -3 and 1 she then graphs the function and gets the graph shown how are the solutions related to the y-intercept?

jenny solves x2 2x 3 0 and finds the solutions are x 3 and 1 she then graphs the function and gets the graph shown how are the solutions related to the yinterce class=

Respuesta :

frika

Answer:

See explanation

Step-by-step explanation:

Jenny solves [tex]x^2 + 2x-3 = 0[/tex] and finds the solutions are [tex]x = -3[/tex] and [tex]x=1.[/tex]

So, she can write this equation as

[tex](x-(-3))(x-1)=0\\ \\(x+3)(x-1)=0[/tex]

The y-intercept is at [tex]x=0.[/tex] Substitute it into the previous equation:

[tex](0+3)(0-1)=3\cdot (-1)=-3[/tex]

From the graph, she can see that y-intercept is at point (0,-3), so y-intercept -3 is the product of solutions to the quadratic equation.

zariahspencer

Answer:

On usatestperp its A: They are the same values.

Step-by-step explanation:

The x-intercepts are were the graph crosses the x-axis. From the graph you can see that it crosses at x = -3 and 1, which are the solutions. Therefore, they are the same values.

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