Respuesta :
Answer: 0.61
Explanation:
This is calculation based on friction.
Since the box rests on a flat surface, the force that exists between them is known as frictional force.
Since the friction is dynamic (velocity is not zero)
The frictional force = kinetic energy gained by the body.
Ff = 1/2mv^2
coefficient of kinetic friction × normal reaction = 1/2mv^2
Since normal reaction is equal to the weight(force acting along the vertical component)
Normal reaction= mg = 50 × 10 = 500N. Therefore,
coefficient of kinetic friction × 500 = 1/2×50×3.5^2
coefficient of kinetic friction = 50×3.5^2/1000
coefficient of kinetic friction= 0.61
The coefficient of kinetic friction between the box and the floor will be 0.61.
What is kinetic friction?
A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion.
The size of the force will be determined by the kinetic friction coefficient between the two materials.
The given data in the problem is;
μ is the coefficient of kinetic friction=?
m is the mass of the box=50-kg
g is the acceleration due to gravity= 9.81 m/s²
v is the speed of the player=3.5m/sec
x is the linear distance traveled=1.50 m
Normal reaction acts on the box;
N=mg
N= 50 × 10
N = 500 N
The friction force is getting converted into the kinetic energy;
Frictional force = Kinetic energy gained
[tex]\rm F_F= \frac{1}{2} mv^2 \\\\ \mu N= \frac{1}{2} mv^2\\\\ \mu \times 500 = \frac{1}{2} (50)(3.5)^2 \\\\ \mu = 0.61[/tex]
Hence,the coefficient of kinetic friction between the box and the floor will be 0.61.
To learn more about the coefficient of kinetic friction refer to;
https://brainly.com/question/19180015
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