Answer:
[tex]\frac{dm}{dt} = 10352 kg/s[/tex]
Explanation:
As we know that thermal energy given to the water to raise its temperature is given as
[tex]Q = ms\Delta T[/tex]
now rate of energy given to the system is
[tex]\frac{dQ}{dt} = \frac{dm}{dt} s \Delta T[/tex]
so we have
[tex]\frac{dQ}{dt} = 1.3 \times 10^8[/tex]
s = 4186 J/kg C
now we have
[tex]1.3 \times 10^8 = \frac{dm}{dt} (4186) 3[/tex]
[tex]\frac{dm}{dt} = 10352 kg/s[/tex]