Answer:
Explanation:
a ) Let the height achieved be h .
We shall apply law  of conservation of mechanical energy.
1 /2 mv² = mgh
h = v² / 2g
v = 110 km/h
= 30.55 m /s
h = [tex]\frac{30.55\times30.55}{2\times9.8}[/tex]
h = 47.61 m
b )
Kinetic energy of car in the beginning
= 1/2 x 750 x (30.55)²
= 349988.43 J
Potential energy at 22 m height
= 750 x 9.8 x 22
= 161700 J
Energy lost due to frictional force
= 349988.43 - 161700
= 188288.43 J
c )
Distance covered along the slope
d = 22 / sin2.5
= 22 / 0.043619
d = 504.36 m
If F be average frictional force
work done by friction
F x d
= F x 504.36
so
F x 504.36 = 188288.43
F = 188288.43 / 504.36
= 373.32 N
