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A radar beacon 40 feet above the ground picks up an airplane approaching at an angle of elevation
of 43 degrees and a distance of 6,390 feet. How high above the ground is the plane in whole feet?

Respuesta :

Diatonic254

5,998.7714 ft

Step-by-step explanation:

Well find x in the illustration;

First To find the opposite side of the right-angled triangle we'll using tangent of the given angle

Tangent Ф = Length of the opposite side / Length of the adjacent side

Tan 43 = h / 6390

h = Tan (43) * 6390

h = 5,958.7714 ft

Then we'll add the height of the beacon which is 40 ft above ground;

x = 5,958.7714 ft + 40 ft

x = 5,998.7714 ft

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