To solve this problem we will apply the geometric concepts of displacement according to the description given. Taking into account that there is an initial displacement towards the North and then towards the west, therefore the speed would be:
[tex]V_T^2=v_N^2-v_W^2[/tex]
[tex]V_T = \sqrt{v_N^2-v_W^2}[/tex]
Travel north 2mph and west to 1mph, then,
[tex]V_T = \sqrt{2^2-1^2}[/tex]
[tex]V_T = \sqrt{3}[/tex]
The route is done exactly the same to the south and east, so make this route twice, from the definition of speed we have to
[tex]v= \frac{\Delta x}{t}[/tex]
[tex]t = \frac{\Delta x}{v}[/tex]
[tex]t = \frac{2*(1mile)}{\sqrt{3}mph}[/tex]
[tex]t = 1.15hour[/tex]
Therefore the total travel time for the man is 1.15hour.
