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liquid ammonia is a common refrigerant because it absorbs so much heat energy when it turns from the liquid to a gas. the heat of vaporation of liquid ammonia is 1374 j/g. Calculate the heat needed to turn 454 grams of liquid ammonia at its boiling point to ammonia gas at the same temperature

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Answer:

The heat required to vaporize 454 grams of liquid ammonia at its boiling point is 624 kJ.

Explanation:

Let's consider the vaporization of ammonia.

NH₃(l) ⇄ NH₃(g)

The heat of vaporization is 1374 J/g. The heat required to vaporize 454 grams of liquid ammonia at its boiling point is:

[tex]454g.\frac{1374J}{g} =6.24 \times 10^{5} J = 624 kJ[/tex]

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