Answer:
int k = 1;
int total = 0;
while (k <= n){
 total = total + (k*k*k);
 k++;
}
Explanation:
The code above has been written in Java.
Following is the line-by-line explanation of the code written as comments.
// Initialize int variable k to 1.
// variable k is used to control the loop.
// It is initialized to 1 because the positive integers should start at 1.
// Starting at zero will be unimportant since the cube of 0 is still zero and
// has no effect on the overall sum of the cubes.
int k = 1;
// Initialize total to zero(0)
// This is so because, at the start of the addition total has no value.
// So giving it zero allows to cumulatively add other values to it.
// Variable total is also of type int because the sum of the cubes of counting
// numbers (which are positive integers) will also be an integer
int total = 0;
// Now create a while loop to repeatedly compute the sum of the cubes
// while incrementing the counter variable k.
// The condition for the loop to execute is when k is less than or equal to
// the value of variable n.
// The cube of any variable k is given by [tex]k^{3}[/tex] which can be
// written as k * k * k.
// At every cycle of the loop, the cube of the counter k is calculated and
// added cumulatively to the value of total. The result is still stored in the
// variable total. After which k is incremented by 1 (k++).
while (k <= n) {
 total = total + (k*k*k);
 k++;
}
The code segment is an illustration of loops
Loops are used for operations that are to be performed repeatedly.
The program in Python where comments are used to explain each line is as follows
#This gets input for n
n = int(input())
#This initializes total to 0
total = 0
#This initializes k to 1 Â
k = 1
#This iterates through n
while(k<=n):
  #This calculates the sum of the cubes
  total = total + k**3
  #This increments k by 1 Â
  k+=1
#This prints the calculated sum
print(total)
Read more about loops at:
https://brainly.com/question/16397886
