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A ball is projected horizontally from a table 1.0 m high and hits the ground after falling from a time t=0.45s. If the ball travels horizontally a distance x = 3.0 m in that time it’s initial velocity was equal to

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skyluke89

The initial velocity is [tex]6.7 m/s[/tex]

Explanation:

The motion of the ball is a projectile motion, therefore it consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

In this problem, we just need to analyze the horizontal motion: the horizontal velocity is constant, therefore the horizontal distance travelled is given by

[tex]x=v_x t[/tex]

where

[tex]v_x[/tex] is the horizontal velocity

t is the time of flight

Here we have:

t = 0.45 s

x = 3.0 m

And so solving for [tex]v_x[/tex], we find

[tex]v_x = \frac{3.0}{0.45}=6.7 m/s[/tex]

And since the ball was initially projected horizontally, this is also the initial velocity.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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