Answer:
Question 1: A. 2
Question 2: C. [tex]x>90[/tex]
Step-by-step explanation:
Question 1:
Amount to be spend = $625
Cost to rent the ball room for 3 hrs = $350
Cost of each additional hour = $125
Ms Jensen wrote the Inequality as,
[tex]625>350+125h[/tex]
h⇒ Number of additional hours.
We need to find the value of 'h'.
Solution:
[tex]625>350+125h[/tex]
Now Subtracting both side by 350 using subtraction property of Inequality we get;
[tex]625-350>350+125h-350\\\\275>125h[/tex]
Dividing both side by 125 using Division property of Inequality we get;
[tex]\frac{275}{125}>\frac{125h}{125}\\\\2.2>h[/tex]
Hence The value of 'h =2' make the Inequality true.
Question 1:
Given:
[tex]20+2<\frac{x}{3}-8[/tex]
We need to find the solution for Inequality.
Solution:
First we will add the like terms we get;
[tex]22<\frac{x}{3}-8[/tex]
Now Adding both side by 8 using addition property of Inequality we get;
[tex]22+8<\frac{x}{3}-8+8\\\\30<\frac{x}{3}[/tex]
Now multiplying both side by 3 Using multiplication property of Inequality we get;
[tex]30\times3<\frac{x}{3}\times 3\\\\90<x[/tex]
Hence The solution to given Inequality is [tex]x>90[/tex].
