Respuesta :
Answer:
Metal A will heat up faster
Explanation:
Step 1: Data given
Mass of the 2 metals = 1.00 grams
The specific heat of metal A is 0.568j/g* °c
The specific heat of metal B is 1.34j/g*°c
Initial temperature = 80 °C
Step 2: Calculate energy needed
A high specific heat value means that it takes MORE energy to raise (or lower) its temperature.
A low value means that it does not take very much energy to heat or cool it.
Step 3: Calculate energy needed to raise 1 °C
Q = m*c*ΔT
Metal A: Q = 1.00g * 0.568 J/g°C * 1°C
Q = 0.568 J
Metal B Q = 1.00g * 1.34 J/g°C * 1°C
Q = 1.34 J
We need 0.568 Joules energy to raise the temperature with 1°C for metal A.
We need 1.34 Joules energy to raise the temperature with 1°C for metal B.
Since we need less energy to raise the temperature for metal A, it will heat up faster.
