contestada

A mixture of He and Ne need to be separated. What will be the ratio of the rates of effusion of He and Ne?

Respuesta :

Answer:

Ratio of rates of effusion of He to Ne is 2.245

Explanation:

According to Graham's law rate of effusion is inversely proportional to square root of molar mass of a gas

So, [tex]\frac{r_{He}}{r_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{He}}}[/tex]

where, [tex]r_{He}[/tex] and [tex]r_{Ne}[/tex] are rate of effusion of He and Ne respectively. [tex]M_{He}[/tex] and [tex]M_{Ne}[/tex] are molar mass of He and Ne respectively.

Molar mass of He = 4.003 g/mol

Molar mass of Ne = 20.18 g/mol

So, [tex]\frac{r_{He}}{r_{Ne}}=\sqrt{\frac{20.18}{4.003}}=2.245[/tex]

So, ratio of rates of effusion of He to Ne is 2.245