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Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another student is 4.0 m away from the talkers. What sound intensity does the other student measure? Assume that the sound spreads out uniformly and undergoes no significant reflections or absorption

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opudodennis

Answer:

[tex]6.1875\times 10^{-8}[/tex]

Explanation:

Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies [tex]I=\frac {k}{r^{2}}[/tex] where r is the distance

Since intensity is given then when at 3 m

[tex]1.1\times 10^{-7}= \frac {k}{3^{2}}[/tex]

[tex]k=3^{2}\times 1.1\times 10^{-7}= 9.9\times 10^{-7}[/tex]

Since we have the constant then at 4m

Intensity, [tex]I= \frac {9.9\times 10^{-7}}{4^{2}}=6.1875\times 10^{-8}[/tex]

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