Answer:
6.15 s
Explanation:
The period of a simple pendulum is given by the equation
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]
where
L is the length of the pendulum
g is the acceleration of gravity
For the pendulum in this problem,
L = 1.5 m (length)
[tex]g=9.8 m/s^2[/tex] (acceleration due to gravity on Earth)
Therefore, its period is
[tex]T=2\pi \sqrt{\frac{1.5}{9.8}}=2.46 s[/tex]
And therefore, the time taken for the pendulum to complete 2.5 oscillations is equal to 2.5 times the period:
[tex]t=2.5T=(2.5)(2.46)=6.15 s[/tex]
