Given that,
7 added to the square of a number is equal to 7 times the number, Â minus 5
Let "x" be the unknown number
From given,
7 added to square of x = 7 times the x minus, 5
[tex]7 + x^2 = 7x - 5[/tex]
Solve the above equation
[tex]x^2 -7x +7+5 = 0\\\\x^2 - 7x + 12 = 0[/tex]
Split the middle term
[tex]x^2 -3x - 4x + 12 = 0\\\\Group\ the\ expressions\\\\(x^2-3x) -(4x - 12) = 0\\\\Take\ the\ common\ factor\ out\\\\x(x -3) -4(x -3) = 0\\\\(x-3)(x-4) = 0[/tex]
We have two solutions
x - 3 = 0
x = 3
And
x - 4 = 0
x = 4
Thus number is 3 or 4