Answer:
J =1.49 J/m²
Explanation:
Given that
Radius of circular cross section ,r= 1.35 mm
Current ,I = 8.55 µA
The current density J is given as
[tex]J=\dfrac{I}{A}[/tex]
A=Area
I=Current
[tex]J=\dfrac{I}{\pi r^2}[/tex]
Now by putting the values in the above equation
[tex]J=\dfrac{8.55\times 10^{-6}}{\pi \times (1.35\times 10^{-3})^2}\ A/m^2[/tex]
J =1.49 J/m²
Therefore the current density will be J =1.49 J/m².
