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A bat is flitting about in a cave, navigating via ultrasonic bleeps. Assume that the sound emission frequency of the bat is 37.5 kHz. During one fast swoop directly toward a flat wall surface, the bat is moving at 0.021 times the speed of sound in air. What frequency does the bat hear reflected off the wall?

Respuesta :

Answer:

39.11 Hz

Explanation:

Data provided in the question:

Frequency of sound emission, [tex]f_0[/tex] = 37.5 kHz = 37500 Hz

Speed of bat, [tex]v_{bat}[/tex] = 0.021 times the speed of sound

Now,

Frequency heard by bat = [tex]f_0\times(\frac{v+v_{bat}}{v-v_{bat}})[/tex]

Therefore,

The Frequency heard by bat will be = [tex]37500\times(\frac{343+0.021\times343}{343-0.021\times343})[/tex]

or

Frequency heard by bat will be= [tex]37500\times\frac{350.203}{335.797}[/tex]

or

Frequency heard by bat will be = 39108.78 Hz = 39.11 Hz

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