Answer:
The minimum value is 0.51
[tex] Q_1= \frac{0.89+1.04}{2}= 0.965[/tex]
Median=Q2= 1.18
[tex] Q_3= \frac{1.41+1.42}{2}= 1.415[/tex]
Max = 1.49
Step-by-step explanation:
We assume the following dataset:
1.18,1.41, 1.49,1.04,1.04,0.74,0.89,1.42,1.45,0.51,1.38
We order the dataset on increasing way and we have:
0.51 0.74 0.89 1.04 1.04 1.18 1.38 1.41 1.42 1.45 1.49
The minimum value is 0.51
The first quartile Q1 can be calculated with the first 6 observations: 0.51 0.74 0.89 1.04 1.04 1.18. The Q1 would be the average between the 3rd and 4th position:
[tex] Q_1= \frac{0.89+1.04}{2}= 0.965[/tex]
For the median since the number of data represent an odd number than the median would be the position in the middle (6th)
Median=Q2= 1.18
The first quartile Q1 can be calculated with the last 6 observations: 1.18 1.38 1.41 1.42 1.45 1.49. The Q1 would be the average between the 3rd and 4th position:
[tex] Q_3= \frac{1.41+1.42}{2}= 1.415[/tex]
And the maximum value for this case would be:
Max = 1.49
We can see the boxplot obtained on the figure attached.
