Answer:
The momentum just before it hits bottom is 3000 kg-m/s.
Explanation:
Given that,
Mass of the mototcycle, m = 100 kg
Is slowly rolls over the edge of a cliff and falls for 3 seconds before it reaches the bottom of a gully. We know that the rate of change of linear momentum is proportional to the applied external force. So,
[tex]F=\dfrac{P}{t}[/tex]
P is momentum
Here, F = mg
[tex]P=mg\times t\\\\P=100\ kg\times 10\ m/s^2\times 3\ s\\\\P=3000\ kg-m/s[/tex]
So, the momentum just before it hits bottom is 3000 kg-m/s. Hence, this is the required solution.