Answer:
Step-by-step explanation:
To find Lenght AC
Let analyse the triangle ABC
Triangle ABC is a right angle triangle at B.
Then, applying Pythagoras theorem
AC²=AB²+BC²
From the graph,
Note that each division on both x and y axis is 1unit
Then,
AB= 8unit
BC= 3unit
So, Applying the Pythagoras theorem for ∆ABC
AC²=AB²+BC²
AC²=8²+3²
AC²=64+9
AC²=73
AC=√73
AC= 8.54units
Approximately AC=8.5units
Now to get BD
Let analyse the triangle BAD
Triangle BAD is a right angle triangle at A.
Then, applying Pythagoras theorem
BD²=AB²+AD²
From the graph,
Note that each division on both x and y axis is 1unit
Then,
AB= 8unit
AD= 6unit
So, Applying the Pythagoras theorem for ∆BAD
BD²=AB²+AD²
BD²=8²+6²
BD²=64+36
BD²=100
BD=√100
BD= 10 units
Then, the answer is 10units and 8.5 units
