The population standard deviation for the scores of a standardized test is 5 points. If we want to be 95% confident that the sample mean is within 2 points of the true population mean, what is the minimum sample size that should be taken

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Answer:

The minimum sample size that should be taken is 24.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

If we want to be 95% confident that the sample mean is within 2 points of the true population mean, what is the minimum sample size that should be taken

This is n when [tex]M = 2, \sigma = 5[/tex]

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]2 = 1.96*\frac{5}{\sqrt{n}}[/tex]

[tex]2\sqrt{n} = 1.96*5[/tex]

[tex]\sqrt{n} = \frac{1.96*5}{2}[/tex]

[tex](\sqrt{n})^{2} = (\frac{1.96*5}{2})^{2}[/tex]

[tex]n = 24.01[/tex]

The minimum sample size that should be taken is 24.

Answer:

The answer is 25. You should round up not down

Step-by-step explanation: