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Use the following information to answer the following questions In those parts of equatorial Africa where the malaria parasite is most common, the sickle-cell allele constitutes 20% of the β hemoglobin alleles in the human gene pool. 15. If the sickle-cell allele is recessive, what proportion of the population should be susceptible to sicle-cell anemia under typical conditions? A. 0.04 B. 0.16 C. 0.20 D. 0.32 E. 0.80

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abdullahfarooqi

Answer:

A. 0.04

Explanation:

The recessive sickle cell allele comprises 20% of the beta hemoglobin alleles in the African gene pool. Under equilibrium, Hardy-Weinberg's principle states that

p^2 + 2pq + q^2 = 1

Here q is a recessive allele. We know 20/100 is the proportion of q i.e. 0.2

Now since sickle cell allele is recessive only the people having homozygous condition i.e. two sickle cell alleles will be affected by anemia.

Hence q^2 will be the proportion of the population susceptible to anemia.

We know q = 0.2

Hence q^2 = 0.04.

Answer:

0.04

Explanation:

Using Hardy-Weinberg Equilibrium equation

p² + 2pq + q²

where p² represent the frequency of the homozygous dominant hemoglobin, 2pq  represent frequency of  heterozygous carrier of the sickle cell and  q² represent frequency of the population susceptible to sickle cell anemia

q = 0.2

the q² = 0.2² = 0.04

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