The question is incomplete as it does not have the options which are provided in attachment.
Answer:
All species are equally related
Explanation:
In the given question, the bases of amino acids have been provided and we know that amino acid is coded by the three nitrogenous bases called codons.
In the given question, the sequence of DNA for:
1. Species A - GTC AGT CAG A, mRNA will be- CAG UCA GUC
2. Species B - GAC TGT GAC T, mRNA will be- CUG ACA CUG
3. Species C - GTC ACA GAG A, mRNA will be- CAG UGU CUC
The amino acid sequence will be-
1. Species A-Glutamine, Serine, Valine
2. Species B-Leucine, Threonine, Leucine
3. Species C- Glutamine, Cysteine, Leucine
From this, it can be deduced that all the species are equally related as the Glutamine is present in species A and C and Leucine in species B and C.