Respuesta :
Answer: The volume of concentrated solution required is 9.95 mL
Explanation:
To calculate the pH of the solution, we use the equation:
[tex]pH=-\log[H^+][/tex]
We are given:
pH = 0.70
Putting values in above equation, we get:
[tex]0.70=-\log[H^+][/tex]
[tex][H^+]=10^{-0.70}=0.199M[/tex]
1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.
Molarity of nitric acid = 0.199 M
To calculate the volume of the concentrated solution, we use the equation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the concentrated nitric acid solution
[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted nitric acid solution
We are given:
[tex]M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL[/tex]
Putting values in above equation, we get:
[tex]7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL[/tex]
Hence, the volume of concentrated solution required is 9.95 mL
