Answer:
0.2 A, clockwise direction
Explanation:
We are given that
Current,I=25 A
Number of turns=n=20
Magnetic field at center of r the loop=B=0
d=2 m
We have to find the direction and magnitude of current flowing in the loop.
Magnetic field due to current I
[tex]B=\frac{\mu_0 I}{2\pi d}\hat{z}[/tex]
Magnetic field due to I'
[tex]B'=-\frac{\mu_0 nI''}{2a}\hat{z}[/tex]
a=1 m
Net magnetic is zero
Therefore, [tex]B+B'=0[/tex]
[tex]\frac{\mu_0 I}{2\pi d}\hat{z}-\frac{\mu_0 nI''}{2a}\hat{z}=0[/tex]
[tex]\frac{\mu_0 I}{2\pi d}\hat{z}=\frac{\mu_0 nI''}{2a}\hat{z}[/tex]
[tex]\frac{I}{\pi d}=\frac{I'n}{a}[/tex]
[tex]I'=\frac{aI}{\pi d n}=\frac{25\times 1}{3.14\times 2\times 20}=0.2 A[/tex]
Where [tex]\pi=3.14[/tex]
Direction: Clockwise