Answer:
Torque on the coil will be ZERO
Explanation:
As we know that the magnetic moment of the closed current carrying coil is always along its axis and it is given as
[tex]M = N i A[/tex]
now we know that magnetic field is also along the axis of the coil so here as we know the equation of torque given as
[tex]\tau = \vec M \times \vec B[/tex]
so we have
[tex]\tau = M B sin0[/tex]
[tex]\tau = 0[/tex]