Respuesta :
The question is incomplete, the complete question is:
Using relative enthalpy and entropy values, determine how the process is affected after each of the following temperature or pressure changes? Consider that a more effective reaction produces more product or more product in a shorter amount of time.
Reaction: SO2 (g) + 2H2S (g) ↔ 3S(s) + 2H2O (g)
Substance | ΔG kJ/mol | ΔH kJ/mol
H2O(g) | -228.6 | -241.8
H2O(l) | -237.1 | -285.8
SO2(g) | -300.4 | -296.9
SO3(g) | -370.4 | -395.2
H2S(g) | -33.01 | -20.17
S(s) | 0 | 0
Categorize into: "More Effective" ~ "Less Effective" ~ "Equally Effective"
- Temp. decreases while maintaining container size
- Temp. increases while maintaining container size
- Pressure decreases while maintaining container size
- Pressure increases while maintaining container size
Answer:
Explanation:
ΔH∘rxn=ΔH∘f(products)−ΔH∘f(reactants)
ΔH∘rxn= [0+2(-241.8)] - [(-296.9) + 2(-20.7)]= -145.6KJ/mol
ΔG∘rxn=[(0+ 2(-228.6) -[(-300.4) + 2(-33.01)]= -90.78KJ/mol
The reaction is spontaneous since ΔG∘rxn is negative
The reaction is exothermic since ΔH∘rxn= negative
1) increase in pressure is less effective because it favours the reverse reaction.
2) increase in temperature is less effective since it favours the reverse reaction given that the reaction is exothermic in nature
3) decrease in pressure is more effective, it favours the forward reaction
4)Decrease in temperature is more effective because it favours the forward reaction.
Answer:
More effective:
- pressure increases by decreasing container size
- temperature decreases while maintaining container size
Less Effective:
- pressure decreases by increasing container size
- temperature increases while maintaining container size
Equally Effective:
- (nothing here)
Explanation:
Hint from question: "The process is exothermic (the change in enthalpy is negative); therefore the equilibrium constant will decrease as the temperature increases. In addition, since the change in entropy is negative, the reaction will become nonspontaneous at some higher temperature. The reaction will be less effective at higher temperatures. The negative change in entropy value also indicates that the reaction will be more effective at higher pressures" - Mastering Chem.
