Riosg0onBris
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Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate the mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.

Respuesta :

carlosego

By definition, the density is given by:

[tex] D = \frac{m}{V}
[/tex]

Where,

m: Helium mass

V: helium volume

Clearing the mass we have:

[tex] m = VD
[/tex]

Transforming the volume to milliliters we have:

[tex] V = (6.3) * (1000) = 6300 mL
[/tex]

Then, replacing values:

[tex] m = (6300) * (1.79 * 10 ^ {-4})

m = 1.1277 g
[/tex]

Answer:

The mass of helium that would take to fill the balloon is:

[tex] m = 1.1277 g [/tex]

kuhaneck500

Answer:

The correct answer is 1.1 grams.

Carlosego failed to round it, sorry for his mistake.

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