Answer:
672 g
Explanation:
We can calculate the mass of water that can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories using the following expression.
[tex]Q = c \times m \times \Delta T[/tex]
where,
c: specific heat of the water
m: mass
ΔT: change in the temperature
[tex]m = \frac{Q}{c \times \Delta T } = \frac{8,064cal}{(1cal/g. \° C) \times (37.0 \° C - 25.0 \° C) } = 672 g[/tex]
The mass of water that can be warmed under these conditions is 672 grams.
