Answer:
[tex]y = \frac{9x}{8} - \frac{3}{8}[/tex]
Step-by-step explanation:
An equation in slope-intercept form has the following format:
[tex]y = mx + b[/tex]
In this problem, we have that:
[tex]x = 8t + 3[/tex]
[tex]y = 9t + 3[/tex]
How can we write in slope-intercept?
In the first equation, i am going to solve t as a function of x. So
[tex]8t = x - 3[/tex]
[te]t = \frac{x - 3}{8}[/tex]
Now i replace in the second equation
[tex]y = 9\frac{x - 3}{8} + 3[/tex]
[tex]y = \frac{9x - 27}{8} + \frac{24}{8}[/tex]
[tex]y = \frac{9x}{8} - \frac{3}{8}[/tex]
